X^2+1x+4=(x+2)(x-1)

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Solution for X^2+1x+4=(x+2)(x-1) equation: 



X^2+1X+4=(X+2)(X-1)

We move all terms to the left:

X^2+1X+4-((X+2)(X-1))=0

We add all the numbers together, and all the variables

X^2+X-((X+2)(X-1))+4=0

We multiply parentheses ..

X^2-((+X^2-1X+2X-2))+X+4=0



We calculate terms in parentheses: -((+X^2-1X+2X-2)), so:

(+X^2-1X+2X-2)

We get rid of parentheses

X^2-1X+2X-2

We add all the numbers together, and all the variables

X^2+X-2

Back to the equation:

-(X^2+X-2)



We add all the numbers together, and all the variables

X^2+X-(X^2+X-2)+4=0

We get rid of parentheses

X^2-X^2+X-X+2+4=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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